5c^2-17c+14=0

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Solution for 5c^2-17c+14=0 equation:


Simplifying
5c2 + -17c + 14 = 0

Reorder the terms:
14 + -17c + 5c2 = 0

Solving
14 + -17c + 5c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(7 + -5c)(2 + -1c) = 0

Subproblem 1

Set the factor '(7 + -5c)' equal to zero and attempt to solve: Simplifying 7 + -5c = 0 Solving 7 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -5c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -5c = 0 + -7 -5c = 0 + -7 Combine like terms: 0 + -7 = -7 -5c = -7 Divide each side by '-5'. c = 1.4 Simplifying c = 1.4

Subproblem 2

Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2

Solution

c = {1.4, 2}

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